Question

Lucy and Zaki each throw a ball at a
target.
0.4
0.6
Lucy's
throw
Hit
Miss
0.2
0.8
0.2
0.8
Zaki's
throw
Hit
Miss
Hit
Miss
What is the probability that both Lucy
and Zaki hit the target?

Answer 1

we can conclude that Probability of both Lucy and Zaki hitting the target is 0.4.

According to the statement

we have to find the probability that the both Lucy and Zaki hit the target.

So, For this purpose, we know that the

Probability is the ratio of the number of outcomes in an exhaustive set of equally likely outcomes that produce a given event to the total number of possible outcomes.

So, From the given information:

When Zaki or Lucy throw a ball at the target there are only two outcomes for each of them ( i.e Hit or miss )

Therefore :

The probability of Lucy hitting the target = 0.4/2

And

The probability of Zaki hitting the target = 0.2+0.2/2

So,

The Probability of both Lucy and Zaki hitting the target is:

P(Lucy ) + P(Zaki ) = 0.4/2 + 0.4/2

P(Lucy ) + P(Zaki ) = 0.8/2

P(Lucy ) + P(Zaki ) = 0.4

Hence,

we can conclude that Probability of both Lucy and Zaki hitting the target is 0.4.

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