The p value of the test is less than the 0.01, therefore the conclusion is to reject the null hypothesis at 0.01 level of significance.
It should be noted that from the information given, the sample is independent and also a random sample. The standard deviation is 0.0182.
The standard deviation will be:
= ✓(0.46)(1 - 0.46)/750
= 0.0182
The test statistic will be:
= (0.2867 - 0.46)/0.0182
= -9.52
The alternative hypothesis shows that the test is two tailed and the p value is -1.645.
Therefore, the p value of the test is less than the 0.01, therefore the conclusion is to reject the null hypothesis at 0.01 level of significance.
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