1. The average velocity of the body falling freely, given the data is 25 m/s
2. The dimensional formula of mass is FL⁻¹T²
1. How to determine the average velocity
We'll begin by calculating the distance travelled by the body. This is illustrated below:
- Initial velocity (u) = 0 m/s
- Acceleration due to gravity (g) = 10 m/s²
- Time (t) = 5 s
- Distance travelled (s) = ?
s = ut + ½gt²
s = ½gt²
s = ½ × 10 × 5²
s = 5 × 25
s = 125 m
Finally, we shall determine the average velocity. Details below:
- Distance travelled (s) = 125 m
- Time (t) = 5 s
- Average velocity (v) =?
v = s / t
v = 125 / 5
v = 25 m/s
Thus, the average velocity of the falling body is 25 m/s
2. How to determine the dimensional formula of mass
- Dimension of force = F
- Dimension of length = L
- Dimension of time = T
- Dimension of mass = ?
Force (F) = mass (M) × acceleration (a)
F = Ma
But
a = m/s²
Thus,
the dimension of acceleration is LT⁻²
Therefore,
F = Ma
F = M × LT⁻²
Divide both sides by LT⁻²
M = F / LT⁻²
M = FL⁻¹T²
3. law of homogeinity
The law of homogeinity states that the dimensions of all the terms in a physical expression should be the same.
Learn more about motion under gravity:
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