The 16th term of the given arithmetic sequence 4, 9, 14, 19... is 79.
The n-th term of an arithmetic sequence, with the first term as a, and the common difference as d, is calculated using the formula:
aₙ = a + (n - 1)d.
In the question, we are asked to find the 16th term of the arithmetic series 4, 9, 14, 19...
The first term of the given arithmetic sequence, a = 4.
The common difference of the given arithmetic sequence, d = 5.
The term to be computed, n = 16.
Therefore, the 16th term of the arithmetic sequence 4, 9, 14, 19... using the formula of the n-th term as aₙ = a + (n - 1)d, can be shown as:
a₁₆ = 4 + (16 - 1)5,
or, a₁₆ = 4 + 15*5,
or, a₁₆ = 4 + 75,
or, a₁₆ = 79.
Thus, the 16th term of the given arithmetic sequence 4, 9, 14, 19... is 79.
Learn more about an arithmetic sequence at
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