Question

A steel cable 3.00 cm2 in cross-sectional area has a mass of 2.40 kg per meter of length. If 500 m of the cable is hung over a vertical cliff, how much does the cable stretch under its own weight?​

Answer 1

When a steel cable with a cross-sectional area of 3.00 cm2 and a mass of 2.40 kg per metre of length is supported by its own weight, it will stretch by 5 cm. if the rope is suspended 500 metres above a sheer cliff.

steel cable

For lifting, use a galvanized steel wire rope with a hook. Corrosion cannot penetrate the galvanized finish. Steel Wire Rope for Lifting with Hook On one end of this steel wire rope, there is a hook and latch for use with winches. Stopped Wire Rope for Lifting The rope is held in place at one end by a stop, often known as a steel cable.

The formula for a wire's elongation under its own weight is

$e = \frac{ugl^{2} }{2aY}$

g = 10ms−2

Ysteel=2.00×1011Nm−2

Where l: original length ;

μ : linear density of the material of the rod.

On substitution,

$e = \frac{2.4*10*(500)^{2} }{2*2*x10{11}*3*10^{-3} }$

e = 5 cm

For a steel cable with a cross-sectional area of 3.00 cm2 and a mass of 2.40 kg per metre of length, the cable's stretch under its own weight is therefore 5 cm. if the rope is suspended 500 metres above a sheer cliff.

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