Question

An antelope moving with constant acceleration of 2m/s2 covers
crosses a point where its velocity is 5m/s. After 6s how much distance it has covered and what is its velocity?

Answer 1

Explanation:

we use the formula for that 6s duration ....

S = ut + 1/2 at²

s = displacement

u = initial velocity

a = acceleration

t = time

so , S = (5 × 6) + (1/2 × 2 × 6 × 6 )

S = 30 + 36

S = 66m

and we can use this formula to find the final velocity.......

V = U + at

V = final velocity

a = acceleration

u = initial velocity

t = time

so , V = 5 + (2×6)

V = 5 + 12

V = 17m/s