The actual height of Caleb is 48 in.
In the question, we are given that in a photograph, Alison stands next to her brother Caleb. Alison is 4cm tall in the photograph and her actual height is 60 in.
In the question, we are asked to find the actual height of Caleb, given he is 3.2 cm tall in the photograph.
Since the photograph is similar to the actual presentation, we will calculate the scale factor for the photo given the actual dimensions.
Scale factor = Actual Dimension/The dimension in the photograph.
The actual height of Alison was 60 in, whereas her height in the photograph was 4 cm.
Thus, the scale factor = (60 in)/(4 cm) = 15 in./cm.
Now, Caleb's height in the photograph = 3.2 cm.
We assume Caleb's actual height to be x in.
Thus, the scale factor = (x in.)/(3.2 cm) = x/3.2 in./cm..
But, the scale factor is computed to be 15 in./cm.
Thus, equating the two, we get the equation:
x/3.2 = 15,
or, x = 3.2*15 = 48.
Thus, the actual height of Caleb is 48 in.
Learn more about scale factor at
https://brainly.com/question/17239314
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