Question

Find three consecutive even integers
whose sum is 66. Find the integers.

Answer 1

So the three numbers are:
20
;
22
;
24

Explanation:
You have to 'jump' an odd number to get to the next even number. So even numbers occur every second place (counting in 2's)
Set the first even number as
n

Then the second is
n
+
2

The third is
n
+
4

(
n
)
+
(
n
+
2
)
+
(
n
+
4
)
=
3
n
+
6
=
66

Subtract 6 from both sides
3
n
=
60

Divide both sides by 3
n
=
20

So the three numbers are:
20
;
22
;
24