Respuesta :
The solution to the questions are:
- Dave's break even (make no revenue) at prices of 1 and 5
- Dave should charge a price of 3 to maximize his revenue
- The most money Dave can make is a revenue of $160
- The prices per donut to make a revenue of $100 are $0.13 and $5.87
1. At what price will Dave break even (make no revenue)?
The revenue function is given as:
R = (p − 1)(200 − 40p)
At break even, R = 0
So, we have:
(p − 1)(200 − 40p) = 0
Split the above equation
p − 1 = 0 and 200 − 40p = 0
Solve for P
P = 1 and P = 5
Hence, Dave break even (make no revenue) at prices of 1 and 5
2. How much should Dave charge to maximize his revenue?
Recall that:
R = (p − 1)(200 − 40p)
Expand the factors
R = 200p - 40p^2 - 200 + 40p
Differentiate the above equation
R' = 200 - 80p + 40
Set the equation to 0
200 - 80p + 40 = 0
Evaluate the like terms
-80p = -240
Divide by -80
p = 3
Hence, Dave should charge a price of 3 to maximize his revenue
3. What is the most money Dave can make?
In (2), we have:
p = 3
Substitute p = 3 in R = (p − 1)(200 − 40p)
R = (3 − 1)(200 − 40 * 3)
Evaluate
R = 160
Hence, the most money Dave can make is a revenue of $160
4. Dave made $100 from donut sales. How much must he have charged per donut?
This means that:
R = $100
So, we have:
100 = (p − 1)(200 − 40p)
Expand the factors
100 = 200p - 40p^2 - 200 + 40p
Evaluate the like terms
40p^2 - 240p + 300 = 0
Divide through by 20
20p^2 - 120p + 150 = 0
Solve for p
p = 0.13 and p = 5.87
Hence, the prices per donut to make a revenue of $100 are $0.13 and $5.87
Read more about revenue function at:
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