Question

an airplane starts from rest and accelerates at a constant 4.50m/s^2 for 35.0s before leaving the ground. how far did it move.

Answer 1

Answer:

d = 2756.25 m

Explanation:

The formula we can use in this case is:

d = v0t + 0.5 at^2

v = at + v0

where,

d = distance travelled

v0 = initial velocity = 0 since at rest

t = time travelled

a = acceleration

v = final velocity when it took off

a. d = 0 + 0.5 * 4.5 * 35^2

d = 2756.25 m