contestada

In a particular electrolysis process, eocathode = -1.151 v and eoanode = 1.548 v. what minimum voltage must be applied to drive the nonspontaneous process?

Respuesta :

The minimum voltage that must be applied to drive the non-spontaneous process is - 0.397.

Electrolysis is the process in which an electric current is used to drive a non-spontaneous chemical reaction.

Electrodes are immersed in the electrolyte and an external supply is connected when the external supply is turned on the circuit gets complete and ions in the electrolyte start attracting the respective oppositely charged electrode. This is the process

E⁰cathode is the standard electrode potential of the cathode.

E⁰anode is the standard electrode potential of the anode.

In short standard electrode potential is the measure of potential at equilibrium.

For calculating standard electrode potential:

E⁰ =  E⁰cathode - E⁰ anode

   = 1.151 - 1.548

  = - 0.397 V

Hence, the minimum voltage that must be applied to drive the non-spontaneous process is - 0.397.

For more information on Electrode potential click on the link below:

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