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What potential difference is required in an electron microscope to give an electron wavelength of 4.5 nm?

Respuesta :

The potential difference is 0.063 V.

The potential difference is defined as the work done in moving a charge of 1 coulomb from one point to another.

An electron microscope is a microscope that uses an accelerated beam of electrons.

The formula given by De Broglie for the wavelength is as follows:

λ is the wavelength.

λ = h / p

 = h / mv

 = h / √2×m×q×V

where h is planks constant

q is the charge

m is the mass

4.5 * 10⁻⁹  = 6.63 * 10⁻³⁴ / √(2×9.31×10⁻³¹×1.6×10⁻¹⁹×V)

On solving for V we get

V = 0.063 V

Hence, the potential difference is 0.063 V.

For more information on de Broglie wavelength click on the link below:

brainly.com/question/4851688

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