Question

Homework:chapter 9.3 hw question 11 score: 0 of 1 point a jar of peanut butter contains g with a standard deviation of g. Find the probability that a jar contains than g. Assume a normal distribution.

Answer 1

The probability that a jar contains more than 461 g is 0.2782.

According to the statement

we have given that the standard deviation and the mean and we have to find the probability that a jar contains more than 461 g by normal distribution.

So, For this purpose, we know that the

Normal distribution is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

And now we find the Z - Score, so,

Z = x - mean / standard deviation.

here x is 461 and mean is 455 and the standard deviation is 10.2 g.

So, Substitute the values in it then

Z = x - mean / standard deviation.

Z = 461 - 455 / 10.2

Z = 6 /10.2

Z = 0.589

For this z score the value of the P is

P = 0.7218

And

So the probability we're looking for is,

Probability = 1 - 0.7218

Probability =  0.2782.

So, The probability that a jar contains more than 461 g is 0.2782.

Learn more about Z - Score here

https://brainly.com/question/25638875

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Question:

A jar of peanut butter contains 455 g with a standard deviation of 10.2 g. find the probability that a jar contains more than 461 g. assume a normal distribution.

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