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A project has a 0.72 chance of doubling your investment in a year and a 0.28 chance of halving your investment in a year. What is the standard deviation of the rate of return on this investment?

Respuesta :

The standard deviation of the return on the investment in which the probability of doubling the investment is 0.72 and the probability that the investment will be halved is 0.28 will be 0.6734.

Given that the probability of doubling the investment is 0.72 and the probability that the investment will be halved is 0.28.

We are required to find the standard deviation of the rate of return on the investment.

Standard deviation can be find out by finding the square root of variance.

Suppose the investment is $1.

Probability           Value

0.72                        2

0.28                       0.5

Expected value=Probability*Value

Expected value=0.72*2+0.28*0.5

=1.44+0.14

=1.58

Variance=E([tex]x^{2}[/tex])-[tex](Ex)^{2}[/tex]

=(0.72*4+0.28*0.25)-[tex](1.58)^{2}[/tex]

=(2.88+0.07)-2.4964

=2.95-2.4964

=0.4536

Standard deviation=[tex]\sqrt{variance}[/tex]

=[tex]\sqrt{0.4536}[/tex]

=0.6734

Hence the standard deviation of the rate of return on the investment is 0.6734.

Learn more about standard deviation at https://brainly.com/question/475676

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