The velocity of rock after 4 sec is 45.2 m/s
Given data : initial velocity(u) = 6m/s
time (t) = 4 sec
final velocity(v)=?
Acceleration due to gravity (g)=9.8m/s^2 (because rock is throwing downward , g is positive)
The first equation of motion (v =u + gt) deals with final velocity, initial velocity, acceleration and time.
We can use the 1st equation of motion to find final velocity, initial velocity, acceleration and time.
Final velocity= initial velocity + gt
v = u + gt
v = 6+9.8*4
v = 45.2 m/s
Hence the final velocity of rock after 4s will be 45.2m/s
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