By using the ideal gas equation referring as,
P\times V=n\times R\times T
Here in,
P = Denotes pressure
V = Denotes volume
n = Denotes the number of moles of gas
R = Denotes gas constant
T = Denotes temperature.
The value at STP will be,
P = 100 kPa
T = 293k
R = 8.314472 L kPa K⁻¹ mol⁻¹
A number of moles in the given gas = 3.43mole
By assembling all values in the given above equation,
V = 3.43 * 8.314 * 293 / 100
V = 83.55 L
Hence, the volume will be 85.55 L of radon gas would be in 3.43 moles at a normal standard room temperature & pressure (293 K and 100kPa).
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