Respuesta :
A. The maximum theoretical yield of the gaseous product in grams is 0.037 g
B. The grams of the excess reagent are left over is 0.97 g
C. The pH of the HBr solution is 1.37
D. The OH¯ concentration of the HBr solution is 2.33×10¯¹³ M
E. The volume (in mL) of the gaseous product is 323 mL
F. The new temperature of the gas is 61 °C
How to determine the mass of HBr
We'll begin by calculating the mole of HBr in the solution. This is illustrated below:
- Volume = 850 mL = 850.6 / 1000 = 0.8506 L
- Molarity = 0.043 M
- Mole of HBr =?
Molarity = mole / Volume
Mole = molarity × volume
Mole of HBr = 0.043 × 0.8506
Mole of HBr = 0.0366 mole
Thus, the mass of HBr can be obtained as follow:
- Mole of HBr = 0.0366 mole
- Molar mass of HBr = 81 g/mol
- Mass of HBr =?
Mass = mole × molar mass
Mass of HBr = 0.0366 × 81
Mass of HBr = 2.96 g
A. How to determine the maximum theoretical yield
Balanced equation
Ca + 2HBr --> CaBr₂ + H₂
Molar mass of Ca = 40 g/mol
Mass of Ca from the balanced equation = 1 × 40 = 40 g
Molar mass of HBr = 81 g/mol
Mass of HBr from the balanced equation = 2 × 81 = 162 g
Molar mass of H₂ = 2 g/mol
Mass of H₂ from the balanced equation = 1 × 2 = 2 g
SUMMARY
From the balanced equation above,
40 g of Ca reacted with 162 g of HBr to produce 2 g of H₂
Next, we shall determine the limiting reactant.
From the balanced equation above,
40 g of Ca reacted with 162 g of HBr.
Therefore,
1.7 g of Ca will react with = (1.7 × 162) / 40 = 6.885 g of HBr.
Since a higher amount of HBr is needed, therefore HBr is the limiting reactant and Ca is the excess reactant
Finally, we shall determine the maximum theoretical yield of the gaseous product. details below
From the balanced equation above,
162 g of HBr reacted to produce 2 g of H₂.
Therefore,
2.96 g of HBr will react to produce = (2.96 × 2) / 162 = 0.037 g of H₂
Thus, The maximum theoretical yield of the gaseous product obtained is 0.037 g
B. How to determine the mass of the excess reactant leftover
Ca is the excess reactant
From the balanced equation above,
162 g of HBr reacted with 40 g of Ca.
Therefore,
2.96 g of HBr will react with = (2.96 × 40) / 162 = 0.73 g
Thus, the mass of the excess reactant leftover can be obtained as illustrated below:
- Mass of excess reactant given = 1.7 g
- Mass of excess reactant that reacted = 0.73 g
- Mass of excess reactant leftover =?
Mass of excess reactant leftover = 1.7 - 0.73
Mass of excess reactant leftover = 0.97 g
C. How to determine the pH of HBr
- Molarity of HBr = 0.043 M
- Hydrogen ion concentration [H⁺] = 0.043 M
- pH =?
pH = –Log H⁺
pH = –Log 0.043
pH = 1.37
D. How to determine the OH¯ concentration
- Hydrogen ion concentration [H⁺] = 0.043
- Hydroxide ion concentration [OH¯] =?
[H⁺] × [OH¯] = 10¯¹⁴
0.043 × [OH¯] = 10¯¹⁴
Divide both side by 0.043
[OH¯] = 10¯¹⁴ / 0.043
[OH¯] = 2.33×10¯¹³ M
E. How to determine the volume of the gas product
- Temperature (T) = 89 °C = 89 + 273 = 362 K
- Pressure (P) = 1.7 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
- Mass of gas product (H₂) = 0.037 g
- Molar mass of H₂ = 2 g/mol
- Number of mole (n) = 0.037 / 2 = 0.0185 mole
- Volume (V) =?
Using the ideal gas equation, the volume of the gas can be obtained as follow:
PV = nRT
Divide both side by P
V = nRT / P
V = (0.0185 × 0.0821 × 362) / 1.7
V = 0.323 L
Multiply by 1000 to express in mL
V = 0.323 × 1000
V = 323 mL
F. How to determine the new temperature
- Initial volume (V₁) = 323 mL = 323 / 1000 = 0.323 L
- Initial pressure (P₁) = 1.7 atm
- Initial temperature (T₁) = 89 °C = 89 + 273 = 362 K
- New Volume (V₂) = 1.54 L
- New pressure (P₂) = 250 mmHg = 250 / 760 = 0.329 atm
- New temperature (T₂) =?
The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
(1.7 × 0.323) / 362 = (0.329 × 1.54) / T₂
Cross multiply
1.7 × 0.323 × T₂ = 362 × 0.329 × 1.54
Divide both side by 1.7 × 0.323
T₂ = (362 × 0.329 × 1.54) / (1.7 × 0.323 )
T₂ = 334 K
Subtract 273 to obtain answer in °C
T₂ = 334 – 273 K
T₂ = 61 °C
Learn more about molarity:
https://brainly.com/question/9468209
Learn more about stoichiometry:
https://brainly.com/question/14735801
Learn more about pH:
https://brainly.com/question/3709867
Learn more about ideal gas equation:
https://brainly.com/question/4147359
Learn more about gas laws:
https://brainly.com/question/6844441
#SPJ1
