The magnitude of the magnetic force per unit length on the top wire is
2×10⁻⁵ N/m
To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula
F= [tex]\frac{\mu_0 I_f}{2\pi d}[/tex]
Here we are given,
[tex]\mu_0[/tex]= magnetic permeability
= 4[tex]\pi[/tex]×10⁻⁷ H m⁻¹
If= 12 A
d= distance from each wire to point.
=0.12m
Now we put the known values in the above equation, we get
F= [tex]\frac{\mu_0 I_f}{2\pi d}[/tex]
Or, F = [tex]\frac{4\pi \times 10^{-7}\times 12}{2\pi \times 0.12}[/tex]
Or, F= 2×10⁻⁵ N/m.
From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.
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