Question

Hydrogen and oxygen react chemically to form water. How much water would form if 4. 8 grams of hydrogen reacted with 38. 4 grams of oxygen?.

Answer 1

43.2 g of H₂0 would form when 4.8 g of Hydrogen reacts with 38.4 g of Oxygen.

What is stoichiometry?

Stoichiometry is defined as the relationship between reactants and products that are used to determine quantitative data.

It is the study of balanced chemical reactions.

To find the mass of the H20 form, we have to use stoichiometry.

First of all, we have to write a balanced chemical reaction

The reaction is as follows:

$2H_2 + O_2 \rightarrow 2H_2O$

The molar mass of O₂ = 32 g

The molar mass of H₂O = 18 g

According to the above reaction,

2 moles of Hydrogen react with 1 mole of Oxygen to form 2 moles of H2O

According to stoichiometry,

32 g of O₂ forms 36 g of H₂O

38.4 g of O₂ forms $\frac{36 \times 38.4 } {32}$of H₂O

                         = 43.2 g of H₂O

Thus, the mass of H₂Oform when 4.8 g of Hydrogen reacts with 38.4 g of Oxygen is 43.2 g

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