the number of electron flow per second through wire is [tex]11.875[/tex] × [tex]10^{18}[/tex]
Given:-
I (current) = 1.90A
t (time) = 1sec.
The current is the quantity of charge Q flowing through a certain point of the wire in a time interval of dt : [tex]I=\frac{Q}{ dt }[/tex].
So, by using this relationship between charge, time and current, we can find the charge (Q) passing any point in the wire in 1 second.
Q = I × dt
= 1.90A × 1sec.
= 1.90C
To find the number of electron corresponds to this charge, we have to divide value by the charge of 1 electron.
[tex]1.6[/tex] × [tex]10^{-19}[/tex] = [tex]1\\[/tex] [tex]e^{-}[/tex]
1.90C = [tex]\frac{1.90}{1.6 * 10^{-19} }[/tex]
= [tex]11.875[/tex] × [tex]10^{18}[/tex].
Thus from the conclusion we can say that the number of electron flow through wire when current is 1.90A is [tex]11.875[/tex] × [tex]10^{18}[/tex].
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