Answer:
[tex]f(4) = \boxed{-13}[/tex]
[tex]g(-2) = \boxed{13}[/tex]
Step-by-step explanation:
Given functions:
[tex]\begin{cases}f(x)=-3x-1\\g(x)=-2x^3-3 \end{cases}[/tex]
To find f(4), substitute x = 4 into function f(x):
[tex]\begin{aligned}f(4) & = -3(4)-1\\& = -12-1\\& = -13\end{aligned}[/tex]
To find g(-2), substitute x = -2 into function g(x):
[tex]\begin{aligned}g(-2) & = -2(-2)^3-3\\& = -2(-8)-3\\& = 16-3\\& = 13\end{aligned}[/tex]
Therefore:
[tex]f(4) = \boxed{-13}[/tex]
[tex]g(-2) = \boxed{13}[/tex]