How many grams of sodium sulfate Na2SO4 (mw = 142.04 g/mol) is needed to prepare 350.0 ml of a solution having a concentration of 0.125 m?

The number of moles of a solute that are dissolved in a given volume is what is meant by the definition of molarity, which is a measurement of a solute's concentration.

By dividing the moles of the solute by the volume of the solution, molarity, also known as the molar concentration of a solution, is obtained.

Molarity = No. of moles of solute / Volume

Molarity is expressed in units mole/litre

In this case, you know that:

molarity= 0.125 M
number of moles of solute= ?
volume= 350 mL= 0.350 mL

Replacing in the definition of molarity:

0.125M = No. of moles of solute / 0.350l

Solving:

number of moles of solute= 0.125 M× 0.350 L

number of moles of solute= 0.04375 moles

Being 142 g/mole the molar mass of Na₂SO₄, that is, the mass of one mole of the compound, the amount of mass that contains 0.04375 moles is calculated as:

mass= 0.04375 moles× 142 g/moles

mass= 6.2125 g

In summary, 6.2125 g of Na₂SO₄ is needed to prepare 350 mL of a solution having a sodium ion concentration of 0.125 M.

To view more about concentrations, refer to;

https://brainly.com/question/10725862

#SPJ4