The minimum total number of bits required for the entire cache to implement an lru line replacement scheme is 4096
Given:
cache is 2-way set associative implies in one set we will have 2 blocks (Hence k = 2).
To Find:
minimum total number of bits
Solution: Least Recently Used (LRU) algorithm is a page replacement technique used for memory management. According to this method, the page which is least recently used is replaced. Therefore, in memory, any page that has been unused for a longer period of time than the others is replaced.
Here Number of sets is = S = Number of blocks / 2 = 4096 / 2 = 2048. Hence Number of bits needed for LRU implementation is = 2048 * 2 * log2 2 = 4096
Hence, minimum total number of bits is 4096
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