At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time?

Speed is the pace at which an object moves along a path in time, whereas velocity is the rate & direction of movement. In other words, velocity is a vector, whereas speed is really a scalar value.

Now according to the question-

Normally, the car's top speed to finish the distance is

= 550mile/10hr

= 55mi/hr

The average time to travel 120 miles at such speed is

t = distance/speed

= 120/55

=2hr, 0.18*60=11mins

= 2hr11mins.

However, the driver discovered that he was 30 minutes behind for this distance, therefore he spent,

2hr 11min +30min= 2hr41mins

He has 10 hours to fulfill the original scheduling time.

(10-2.41)hrs = 7hr19mins to cover the remaining distance of

{550-120}=430mile.

First, 7hr19mins= {7*(19/60)}hr

= {439/60}hr

Let us now calculate the pace where the driver must go in order to compensate for his initial delay.

Speed= distance/time

= 430/{439/60}

Re-arranging;

Speed = 430/439/60

Use the law of reciprocal,

Speed = (430*60)/439

= 25800/439

= 58.7699mi/hr

However, we were instructed to leave their answer in three significant figures. Therefore, Speed = 58.8mi/hr.

To know more about the speed, here

https://brainly.com/question/13943409

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The complete question is-

A truck driver has a shipment of apples to deliver to a destination 550 miles away. The trip usually takes him 10.0 hours. Today he finds himself daydreaming and realizes 120 miles into his trip that that he is running 30.0 minutes later than his usual pace at this point. If the driver still wishes to complete the trip in 10.0 hours, how fast must he drive for the rest of the trip? (In all questions, you may assume that the truck moves with a constant speed.)

At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time? Express your answer using three significant figures.