Option(A) is the correct answer.
For some time, sodium/potassium ATPase must begin to function. Naturally, this membrane-bound enzyme catalyzes the conversion of three internal Na+ ions into two external K+ ions. As a result, the amount of intracellular sodium will decrease and intracellular potassium will increase. A transporter that is active is this enzyme. Therefore, ATP will be employed as the source of energy for active transport.
Normally, the sodium potassium ATPase maintains a potassium gradient inside the cell (20X more potassium inside than outside), allowing potassium to passively flow out of the cytoplasm through open potassium channels. In live cells, this K+ leakage keeps the membrane potential stable. As in your case, sodium should be greater outside the cell. As a result, co-transport systems can be powered by the sodium gradient, conserving ATP. (Of course, if sodium channels open, the sodium also depolarizes the membranes of neuronal cell membranes.) Although I am unsure of what the typical concentration of salt in a cell is, your figure appears pretty high. Since the external salt content should be nine times greater than the inside, I believe it needs to be decreased.
To learn more about ATP:
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