Question

Magnesium hydroxide mg(oh)2 is an antacid that is used to relieve indigestion, sour stomach and hurtburn. it can be prepared by reacting magnesium chloride, mgcl2 and sodium hydroxide,naoh with the by-product of sodium chlrodie,nacl. in an experiment, a student allowed 15.1g of mgcl2 to react with 9.35 g naoh. calculate the mass in grams of mg(oh)2 that could be obtained at the end of the experiment.

Answer 1

0.259 mol of Mg(OH)2 is formed.

What is an antacid?

Antacids are medications that counteract (neutralize) your stomach's acid to ease heartburn and indigestion. They are available without a prescription from pharmacies and stores and come in liquid or chewable tablet form.

Given :

mass of MgCl2 used = 15.1 g

mass of NaOH used = 9.35 g

Formula used :

MgCL2 + NaOH = NaCl + Mg(OH)2

Solution:

58.3 g of MgCl2 gives 1 mol of Mg(OH)2 , so

How many moles of Mg(OH)2 will 15.1g of MgCl2 give?

no. of moles of Mg(OH)2 formed = 15.1 / 58.3 = 0.259 mol

Therefore, the quantity of Mg(OH)2 formed is 0.259 .

To learn more about antacids :

https://brainly.com/question/28187760

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