Question

If 70.9 g of chlorine reacts with sufficient cesium to produce cesium chloride, what is the theoretical yield?

Answer 1

336.69 g ≈337 g

337 g is the theoretical yield.

2 Cs + Cl2 ---> 2 CsCl

Two moles gives two moles

Convert moles into mass:

molar mass of cs = 132.91 g/mol

molar mass of cl = 35.453 g/mol

molar mass of 2CsCl

= 2 * 168.36

= 336.72

Now,

2 Cs + Cl2           --->     2 CsCl

cl2 =70.906                  2 * 168.36

70.906                         336.72

If 70.906g of chlorine produces 336.72 g of 2CsCl,

70.9 g of chlorine produces how much 2CsCl?

On applying Unity formula

70.906 g of Cl ≅ 336.72 g of 2CsCl

70.9 g of Cl ≅ X of 2CsCl

∴X = 70.9 × 336.72 / 70.906

X = 336.69 g

The theoretical yield of 2CsCl = 336.69 g

To learn more about theoretical yield visit:

https://brainly.com/question/14966377

#SPJ4