The concentration of hydroxide ion in a saturated solution of zinc Hydroxide Ksp can be calculated is 8.43 106
using the dissociation equation as follows:
Zn(OH)2 > Zn2++2 OH > Ksp = [Zn2+] [OH] 2 ICE Chart:
→ Initially, [Zn2+] and [OH] equal 0.
Modifications to [Zn2+]=+s and [OH]=+2s
Therefore, equilibrium values are [Zn2+]=s and [OH]=2s.
Our Ksp equation can be solved by entering equilibrium values:
Ksp=3.0∗10−16=
[s]∗[2s]
2 s=4.22∗10−6
Calculate the OH- concentration: [OH]=2s (from above) = 8.43 106
Utilize [OH] to determine pOH and then pH:
pOH=log([OH])=5.07 pH=14 pOH=8.93
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