The resonant frequencies of a tube closed at one end are 400 hz apart. if both ends of the tube are then opened, the new 1st harmonic frequency is?

Respuesta :

The new harmonic fundamental frequency is 800 Hz.

The formula f = v/2*L, where L is the length of the tube or device the wave is going through, is used to determine the fundamental frequency. Most vibrating objects have more than one resonant frequency and those used in musical instruments typically vibrate at harmonics of the fundamental.

v is the fundamental frequency 400Hz= v/4L    

It functions as a closed organ pipe since one end of it is closed.

The open tube's fundamental frequency is v / 2L

In light of (1), v / 4L=400Hz

Hence, v/2L =2×400Hz=800Hz

Therefore, the open tube's fundamental frequency is 800 Hz.

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