Question

Find the average acceleration, in meters per second squared, in the x-direction between t1 = 0.15 s and t2 = 1.9 s.

Answer 1

Answer:

There isn't enough information to solve.  Is this related to a graph?  The initial and final velocities are needed.  The expression for solving is noted under Explanation.

Explanation:

Given final velocity, initial velocity and displacement, one can solve for the acceleration using:

a=v2−u22s,

where v is final velocity (m/sec), u is initial velocity (m/sec) and s it the distance travelled (in m).