Question

The density of lithium is 0.546 g/cm^3. What volume is occupied by 3.66 x 10^23 atoms of lithium?

Answer 1

The density of lithium is 0.546 g/cm^3. The volume occupied by 3.66 x $10^{23}$  atoms of lithium is 7.73.

The mass of a substance per unit volume is referred to as its density. It is frequently represented by the sign ρ.

A substance's density can be calculated using,

ρ = $\frac{m}{V}$

The amount of matter in a substance is determined by its mass. Typically, it is expressed in grams (g) or kilograms (kg). A substance's volume is determined by how much 3D space it takes up. The number of atoms, molecules, or ions is measured using the mole as a unit of measurement. The amount of stuff that has the same number of elementary particles as there are atoms in 12 grams is referred to as a mole.

1 mole = 6.022 x $10^{23}$ atoms/number Avogadro's

Molar Mass of Lithium = 6.94 g/mol

1 mole of Lithium has atoms

3.66 x $10^{23}$ atoms of lithium has molar mass = $\frac{6.94}{6.022 * 10^{23} }$× 3.66 ×$10^{23}$

m = 4.218 g

ρ = $\frac{4.218 }{ 0.546}$

ρ = 7.73 $cm^{3}$

lithium therefore fills 7.73 volume units with 3.66 × $10^{23}$ its atoms.

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