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Calculate the centripetal force (in n) on the end of a 45.0 m (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass is 3.0 kg.

Respuesta :

The centripetal force on the turbine blade is 1332.3 N.

A force that causes a body to follow a curved path is known as a centripetal force. It always moves in a direction that is the opposite of the body's velocity and in the direction of the immediate center of curvature of the path.

When a constant speed circular motion is applied to an item, the centripetal force always acts inward since the object's velocity is tangential to the circle. This would imply that the direction of the force is always perpendicular to the direction in which the object is being moved.

The formula for centripetal force is

F = mω²r ........................ Equation 1

Where F = Centripetal force, ω = angular velocity, r = radius.

Where π = 3.1415

Given: m = 3 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 45m.

Substitute into equation 1

F = 3(3.1415)²(45)

F = 1332.3 N

Hence the centripetal force on the turbine blade = 1332.3 N

To know more about centripetal force refer to:  https://brainly.com/question/11324711

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