The de broglie wavelength (in picometers) of a hydrogen atom traveling at 430 m/s is 922pm.
This is an important concept during the study of quantum mechanics.
According to de-broglie, wavelength is inversely proportional to the mass as well as velocity.
wavelength = h/mv
where,
h is planck's constant.
m is the mass of the atom
v is the velocity
Given,
velocity = 430 m/s
mass of hydrogen atom = 1.67 × 10^(-27)
h = 6.626 × 10^(-34)
By substituting all the values in equation, we get
wavelength = 6.626 × 10^(-34)/ (430 × 1.67 × 10^(-27))
= 0.00922 × 10^(-7)
= 922pm.
Thus, we calculated that the de broglie wavelength (in picometers) of a hydrogen atom traveling at 430 m/s is 922pm.
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