Question

What is the value of 36x - 8y to the power of 2, when x=3 and y= -6

Answer 1

$36x-8y^2 \hbox{ when } x=3 \hbox{ and } y=-6 \\ \\ 36 \times 3 -8 \times (-6)^2=3 \times 36 - 8 \times 36=(3-8) \times 36= -5 \times 36=\\ =\boxed{-180}$

Answer 2

$(36x-8y)^{2}$

$[36(3)-8(-6)]^2$

$(108+48)^2$

$156 ^{2}$

$=24336$