Respuesta :

Step-by-step explanation:

1st expression ,

[tex] 2 {x}^{2} + x - 3[/tex]

[tex]2 {x}^{2} + (3 - 2)x - 3[/tex]

[tex]2 {x}^{2} + 3x - 2x - 3[/tex]

[tex]x(2x + 3) - 1(2x + 3)[/tex]

[tex](x - 1) \: (2x + 3)[/tex]

2nd expression

[tex]4 {x}^{2} - 9[/tex]

Using the formula

[tex] {a}^{2} - {b}^{2} = (a + b) \: (a - b)[/tex]

[tex](2x {)}^{2} - (3 {)}^{2} [/tex]

[tex](2x + 3) \: (2x - 3)[/tex]

Now ,

HCF = CF

HCF = ( 2x + 3 ) ...

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