Question

two perfumes A and B were released at the same time and you are standing 7.5metres away from both of them.molarmass of perfume A is 275g/mol and molarmass of perfume B is 205g/mol.if you smell first perfume in 15 seconds,how long will take to smell second perfume?

Answer 1

17.40 sec is the time will take to smell second perfume after diffusion takes place

Acc. to Graham's law of Diffusion

Diffusion of Gas inversely proportional to square root of its Molecular mass.

rb (Perfume B)

ra(perfume A)

= $\sqrt{\frac{Ma}{Mb} }$ its equation (1)

Give molar mass of Perfume A = 275 g/mol

molar mass of Perfume B= 205g/mol putting value in (1)

» $\frac{rb}{ra}=\sqrt{\frac{275}{205} }$

$\frac{rb}{ra} =1.16$ its eq (2)

» Perfume B will defuse 1:16 times faster than perfume A.

Hence, perfume B will be first smelled by Person.

Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton

$\frac{ra}{rb}=\frac{tb}{ta}$

Now,, from eq(2) toto

1/1:15 = $\frac{tb}{ta}$

ta

Given tb =the smell of Perfume B as it diffuse faster  

ta= 1.15 x 15 see  

=ta2=17.40 sec

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