Respuesta :
Answer:
E =+823.12N/C.
Explanation:
Answer:
E =+823.12N/C.
Explanation:
The electric field EE at point PP is the sum of electric field E_1E
1
due to q_1q
1
and E_2E
2
due to q_2q
2
at PP :
E = E_1+E_2E=E
1
+E
2
.
The distance from PP to q_1q
1
is R_1 = 0.150m+0.250m = 0.400mR
1
=0.150m+0.250m=0.400m ; therefore, the electric due to it is
E_1 = k\dfrac{q_1}{R_1^2}E
1
=k
R
1
2
q
1
E_1 = 9*10^9*\dfrac{+6.39*10^{-9}C}{(0.400m)^2}E
1
=9∗10
9
∗
(0.400m)
2
+6.39∗10
−9
C
E_1 = +359.44N/C.E
1
=+359.44N/C.
And the distance from PP to q_2q
2
is R_2 = 0.250mR
2
=0.250m ; therefore,
E_2 = k\dfrac{q_2}{R_2^2}E
2
=k
R
2
2
q
2
E_2 = 9*10^9*\dfrac{+3.22*10^{-9}C}{(0.250m)^2}E
2
=9∗10
9
∗
(0.250m)
2
+3.22∗10
−9
C
E_2 = +463.68N/CE
2
=+463.68N/C
Hence, the total electric field at point PP is
E = E_1+E_2E=E
1
+E
2
E = +359.44N/C+463.68N/CE=+359.44N/C+463.68N/C
\boxed{E =+823.12N/C.}
E=+823.12N/C.
where the plus sign indicates that the the electric field points to the right.
The Net Electric potential at point P will be 181.2 Volts.
We have two charges.
We have to calculate the Electric Potential at point P.
What is the formula to calculate the electric potential due to point charge ?
The Electric potential due to point charge is given by -
[tex]$V =\frac{1}{4\pi \epsilon_{o} } \frac{q}{r}[/tex]
According to the question -
The Electric potential due to point charge Q(1) -
V(1) = [tex]$9\times 10^{9} \times \frac{6.39\times 10^{-9} }{0.424}[/tex]
V(1) = 135.64 Volts
The Electric potential due to point charge Q(2) -
V(2) = [tex]$9\times 10^{9} \times \frac{3.22\times 10^{-9} }{0.636}[/tex]
V(2) = 45.56 Volts
Net Electric Potential at point P = V(n) = V(1) + V(2) = 135.64 + 45.56 = 181.2 Volts.
Hence, the Net Electric potential at point P will be 181.2 Volts.
To solve more questions on Electric Potential, visit the link below-
https://brainly.com/question/14019286
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[ The question given is not clearly written. The complete question is -
" In the diagram, q1 = +6.39*10^-9 C and q2 = +3.22*10^-9 C. What is the electric field at point P? Include a + or - sign to indicate the direction.
Q1-p-Q2. Q1 to p has a distance of 0.424 m. P to Q2 has a distance of 0.636 m. " ]
