The work done on the gas is 567.42 J and the change in the internal energy would be 167.42 J
It is the total energy of the substance that is contained in the system which is the sum of all the kinetic energy and potential energy of the molecules and the atoms contained in it.
As given in the problem a gas is compressed at a constant pressure of 0.800atm from 9.00 L to 2.00 L. In the process, 400 J of energy leaves the gas by heat.
1 atm = 101325.00 N/m²
0.800 atm = 0.800×101325.00
=81060 N/m²
The work done by the gas under constant pressure
W = P×( V₂ -V₁)
=81060×(2- 9)×10⁻³
= - 567.42 J
A negative sign represents that work is done on the gas
By using the first law of the thermodynamics
ΔQ = ΔU +W
-400 = ΔU - 567.42
ΔU = 167.42 J
Thus, The work done on the gas is 567.42 J and the change in the internal energy would be 167.42 J
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