Using the concept of divisibility by 6, we have that:
What is the rule for divisibility by 6?
A number is divisible by 6 if it is divisible by 2 and 3, hence:
- A number is divisible by 2 if it is even, that is, the last digit is 0, 2, 4, 6 or 8.
- A number is divisible by 3 if the sum of the digits is divisible by 3, that is, is a multiple of 3.
For this problem, since the number finishes in 6, we know that it is divisible by 2. The sum of the digits is:
8 + 4 + 3 + a + 6 = a + 21.
Then:
- With a = 0, the sum is of 21, which is a multiple of 3, hence the smallest digit is of 0.
- With a = 9, the sum is of 30, which is a multiple of 3, hence the greatest digit is of 9.
More can be learned about divisibility by 6 at https://brainly.com/question/9462805
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