Substituting x=6 and y=1 into both equations,
[tex]x+2y=8 \\ \\ 6+2(1)=8 \\ \\ 8=8 \\ \\ \\ \\ 5x-2y=4 \\ \\ 5(6)-2(1)=4 \\ \\ 28=4[/tex]
Since the second equation is not satisfied, (6,1) is not a solution to the system of equations.
Answer:
yes
Step-by-step explanation:
(6,1) is a solution to the system of equations shown only for equation one in the sense that x=6 any y=1
x+2y=8
6+2(1)=8
