The coordinates of the image of EB are E' = (-1, -1) and B' = (-7, 17)
The coordinates of the pre-image are given as:
E(2, -1) and B(0, 5)
The dilation is given as:
Center, (a, b) = (3,-1)
Scale factor, k = 3
The coordinates of the image of EB is calculated using:
(x, y) = (k(x - a) + a, k(y - b) + b)
So, we have:
E' = (3 * (2 - 3) + 2, 3 * (-1 - -1) - 1)
E' = (-1, -1)
Also, we have:
B' = (3 * (0 - 3) + 2, 3 * (5 - -1) - 1)
B' = (-7, 17)
Hence, the coordinates of the image of EB are E' = (-1, -1) and B' = (-7, 17)
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