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A 2.20kg mass oscillates on a spring of spring constant k= 250.0N/m with a period of 0.615s. Is this system damped or not? how do you know?if it is damped, find the damping constant B​

Respuesta :

The system of the oscillating mass and the spring is damped.

The value of damping constant B​ is 13.3 kg/s.

What is damping in simple harmonic motion?

Damping in simple harmonic motion is restraining of oscillatory motion by dissipation of energy due to resistive forces such as air resistance or friction.

In the system of the oscillating mass and the spring, since the system is oscillating, it is NOT critically damped or overdamped.

If there were no damping occurring, the mass should be oscillating with a period, T = 2π√(m/k)

T =  2π√(2.20/25) = 0.589 s

Since, the system is oscillating more slowly than the period above, the system is damped.

To determine the value of the damping constant, B:

With damping, the new frequency is given as follows:

ω' = √(k/m - B²/4m²)

Also, ω' = 2π/T

ω' = 2π/0.615 = 10.22 rad/s

Solving for B in the equation above:

B = 2m√{k/m - (ω')²}

B = 2 * 2.20 √{(250/2.20) - (10.22)²

B = 13.3 kg/s

In conclusion, damping of motion results in restraining of motion due to loss of energy.

Learn more about damping at: https://brainly.com/question/24098142

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