What is the molarity of a solution formed by mixing 10.0g of H2SO4 with enough water to make 0.100L of solution?

The amount of material in a given amount of answer is denoted by its molarity (M). The moles of a solute per liter of solution is what is meant by "molarity." A solution's molarity is the same as its molar concentration.

What is the molarity of a solution formed by mixing 10.0g of H2SO4 with enough water to make 0.100L of the solution?

Generally, the equation for Moles number is mathematically given as

n = m / M

Therefore

n = 10g / 98g/mol

n= 0.102mol

Where

V=0.1L

Therefore

[tex]C_m = \frac{n }{ V }\\\\C_m= \frac{0.102mol}{ 0.1.1L }[/tex]

C_m= 1.02M

In conclusion, the molarity of a solution formed by mixing 10.0g of H2SO4 with enough water to make 0.100L of the solution is

C_m= 1.02M