- The null and alternative hypotheses would be given by H₀: μ = 7 and H₀: μ ≠ 7.
- The test statistic is equal to 1.198.
- The p-value is equal to 0.1262.
- In conclusion, yes the mean discharge differs from 7 fluid ounces.
What is a null hypothesis?
A null hypothesis (H₀) can be defined the opposite of an alternate hypothesis (H₁) and it asserts that two (2) possibilities are the same.
How to calculate value of the test statistic?
The test statistic can be calculated by using this formula:
[tex]t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }[/tex]
Where:
- is the standard deviation.
- n is the number of hours.
For this clinical trial (study), we should use a t-test and the null and alternative hypotheses would be given by:
H₀: μ = 7
H₀: μ ≠ 7
Next, we would calculate the t-test as follows:
[tex]t=\frac{7.08\;-\;7}{\frac{0.25}{\sqrt{14} } }\\\\t=\frac{0.08}{\frac{0.25}{3.7417 } }[/tex]
t = 0.08/0.0668
t = 1.198.
For the p-value, we have:
P-value = P(t < 1.198)
P-value = 0.1262.
Therefore, the p-value (0.1262) is greater than α = 0.10. Based on this, we should fail to reject the null hypothesis.
In conclusion, yes the mean discharge differs from 7 fluid ounces.
Read more on null hypothesis here: https://brainly.com/question/14913351
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