Question

Simplify $\frac{6a^2 b^-^2}{8a^-^3 b^3}$ Assume a≠0 and b≠0

Answer 1

Answer:

sorry i thought i knew it

Step-by-step explanation:

Answer 2

Answer:

3rd option

Step-by-step explanation:

using the rules of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ : nm > n

$\frac{a^{m} }{a^{n} }$ = $\frac{1}{a^{(n-m)} }$ : n > m

$\frac{6a^2b^{-2} }{8a^{-3b^3} }$ ← separate the variables

= $\frac{6}{8}$ × $\frac{a^2}{a^{-3} }$ × $\frac{b^{-2} }{b^3}$

= $\frac{3}{4}$ × $a^{2-(-3)}$ × $\frac{1}{b^{3-(-2)} }$

= $\frac{3}{4}$ × $a^{2+3}$ × $\frac{1}{b^{3+2} }$

= $\frac{3}{4}$ × $a^{5}$ × $\frac{1}{b^{5} }$

= $\frac{3a^{5} }{4b^{5} }$