Question

Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of 3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2)

Answer 1

The required orbital speed of the ice cube is 355,358m/s

What is gravitational law?

The force of gravitation is directly proportional to the product of the masses and inversely proportional to the distance between them. This can be expressed mathematically as;

Fr = GMm/r²

The distance is calculated as;

s = Gm/r²

Solving both equation, we will have:

v²/r = Gm/r²

v² = Gm/r

Take the square root of both sides

v = √Gm/r

Solve the required orbital speed

V =  √6.67×10^-11 * 5.68 x 10^26 / 3.00 x 10^5

V = 355358.97m/s

Hence the required orbital speed of the ice cube is 355,358m/s

Learn more on orbital speed here: https://brainly.com/question/22247460

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