The orbital speed of an ice cube in the rings of saturn is approximately 3.56 * 10^6 m/s
The law of gravitation states that the force of gravitation is directly proportional to the product of the masses and inversely proportional to the distance between the masses. Mathematically;
F = GMm/r²
where
M and m are the mass of ice cube and
Recall that;
s = Gm1/r^2
Also;
F = sm²
Substitute to have;
s = m²/F
For the centripetal acceleration
a = v²/r
Such that;
v²/r = Gm/r²
v² = Gm/r
v = √Gm/r
Substitute the given parameters into the formula to have:
V = √6.67×10^-11 * 5.68 x 10^26 / 3.00 x 10^5
V = 355358.97m/s = 3.56 * 10^6 m/s
Therefore the orbital speed of an ice cube in the rings of saturn is approximately 3.56 * 10^6 m/s
Learn more on orbital speed here: https://brainly.com/question/7260440
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