By applying trigonometric identities, the value of tan(x) = 14, gives;
[tex]sin(2 \cdot x) = \frac{28}{197} [/tex]
[tex]cos(2 \cdot x) = -\frac{195}{197} [/tex]
[tex]tan(2 \cdot x) = -\frac{28}{195} [/tex]
Given;
tan(x) = 14
sin(x) is negative
By definition, we have;
[tex]sin(2 \cdot x) = \mathbf{\frac{2 \cdot \: tan(x)}{1 + {tan(x)}^{2} }} [/tex]
Which gives;
[tex]sin(2 \cdot x) = \frac{2 \times 14}{1 + {14}^{2} } = \frac{28}{197} [/tex]
Similarly, we have;
[tex]cos(2 \cdot x) = \mathbf{\frac{1- tan(x)^2}{1 + {tan(x)}^{2} }} [/tex]
Which gives;
[tex]cos(2 \cdot x) = \frac{1- 14^2}{1 + {14}^{2} } = -\frac{195}{197} [/tex]
[tex]tan(2 \cdot x) = \mathbf{\frac{sin(2 \cdot x) }{cos(2 \cdot x) } } [/tex]
Which gives;
[tex]tan(2 \cdot x) = \frac{ \frac{28}{197}}{-\frac{195}{197} } = -\frac{28}{195} [/tex]
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