The coordinates of the vertices of △MER are M(3,2), E(3,−3), and R(9,−3). Find the side lengths to the nearest hundredth and the angle measures to the nearest degree. Answers;
A) ME = 5; ER = 6, MR ≈ 7.81 m∠E = 90°, m∠M ≈ 50°, m∠R ≈ 40°
B) ME = 6; ER = 5, MR ≈ 7.81 m∠E = 90°, m∠M ≈ 51°, m∠R ≈ 39°
C) ME = 6; ER = 5, MR = 11 m∠E = 90°, m∠M ≈ 50°, m∠R ≈ 40°
D) ME = 5; ER = 6, MR ≈ 7.81 m∠E = 90°, m∠M ≈ 40°, m∠R ≈ 50°

Please give a full explanation I would really appreciate it :)

Respuesta :

Using the Pythagorean theorem and the law of sines, the correct lengths to the nearest hundredth and the angle measures to the nearest degree are: A) ME = 5; ER = 6, MR ≈ 7.81 m∠E = 90°, m∠M ≈ 50°, m∠R ≈ 40°

What is the Pythagorean Theorem?

The theorem states that the square of the longest side of a right triangle equals the sum of the squares of the lengths of the other two smaller sides of the right triangle.

The points, M(3,2), E(3,−3), and R(9,−3) has been plotted on the graph which shows that angle E  is a right triangle, therefore:

m∠E = 90 degrees.

Find ME and ER:

ME = 5 units

ER = 6 units.

Using the Pythagorean theorem, find MR:

MR = √(ME² + ER²)

MR = √(5² + 6²)

MR = √(25 + 36)

MR = 7.81 units

Using the law of sines, find m∠M:

sin M/ER = sin E/MR

sin M/6 = sin 90/7.81

sin M = (sin 90 × 6)/7.81

sin M = 0.7682

M = sin^(-1)(0.7682)

m∠M ≈ 50°

m∠R = 180 - 50 - 90

m∠R = 40°

Thus, the correct lengths to the nearest hundredth and the angle measures to the nearest degree are:

A) ME = 5; ER = 6, MR ≈ 7.81 m∠E = 90°, m∠M ≈ 50°, m∠R ≈ 40°

Learn more about the Pythagorean theorem on:

https://brainly.com/question/343682

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