The given figure is a solid object formed by a cylinder and a hemisphere. If the total length of that solid object is 64 cm and length of the cylinder is 50 cm, find the total surface area of the solid object.

The total surface area of the solid object is 2660.925 square cm the answer is 2660.925 square cm.
In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.
We know the volume of the cylinder is given by:
[tex]\rm V = \pi r^2 h[/tex]
The surface area of the
= surface area of half sphere + surface area of the cylinder - surface area
of one circular base
The radius r = (64-50)/2 = 7 cm
= (1/2)[4π(7)²] + 2π(7)(50) + 2π(7)² - π(7)²
= (1/2)[615.75] + 2506.99 - 153.94
= 307.875 + 2506.99 - 153.94
= 2660.925 square cm
Thus, the total surface area of the solid object is 2660.925 square cm the answer is 2660.925 square cm.
Learn more about the cylinder here:
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