The given figure is a solid object formed by a cylinder and a hemisphere. If the total length of that solid object is 64 cm and length of the cylinder is 50 cm, find the total surface area of the solid object.​

The given figure is a solid object formed by a cylinder and a hemisphere If the total length of that solid object is 64 cm and length of the cylinder is 50 cm f class=

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The total surface area of the solid object is 2660.925 square cm the answer is 2660.925 square cm.

What is a cylinder?

In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.

We know the volume of the cylinder is given by:

[tex]\rm V = \pi r^2 h[/tex]

The surface area of the

= surface area of half sphere + surface area of the cylinder - surface area

  of one circular base

The radius r = (64-50)/2 = 7 cm

= (1/2)[4π(7)²] + 2π(7)(50) + 2π(7)² - π(7)²

= (1/2)[615.75] + 2506.99 - 153.94

= 307.875 + 2506.99 - 153.94

= 2660.925 square cm

Thus, the total surface area of the solid object is 2660.925 square cm the answer is 2660.925 square cm.

Learn more about the cylinder here:

brainly.com/question/3216899

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